which winch

[blackbob]

what would be the best winch for a suuki vitara ie pounds pulling power

[dxmedia]

1.2 - 1.5 times the total weight you will be pulling.

[fuzzy]

a 9000lb winch should be more than enough to get you out of most situations. personally i would have a look at a superwinch ep9, I had one on the front of my old 90 for years and after i had sealed the solenoid box with silicone it never let me down.

[glaggs]

Champion winch's are good. Come with 'solid state' water proof solinoid pack and remote on most models.

[Saffy]

what would be the best winch for a suuki vitara ie pounds pulling power

This one should suit the needs...

[Range Rover Blues]

There's always one :roll:






 :lol:

[andycwb]

I went for a Tabor winch.  Better quality than the anonymous Chinese cheap ones, and a lot cheaper than the Warn ones that come off the same production line.   I was going to go with Superwinch until I realised it wouldn't fit between the chassis rails in a discrete mount on the Disco.

[littlepow]

what about one of these, if you only want it for very occasional use.

[dxmedia]

Those hand winches are great, apart from the MASSIVE rolll of cable which you have to have with you all the time.

A small electric winch can be had from ebay for under a ton, if it's for an SJ 4K would suffice (I've a 6K on a 2 tonne Jeep and it's NEVER failed to get me unstuck on a single line pull) you don't need an 8 or 9K winch for a 4x4, and 15K's... really... I've a 14K for the front of the mog and that will never be used to it's maximum.

Large amounts of people fit large winches because that's what you need isn't it!!   1.2 - 1.5 times the gross weight of the vehicle is the maximum amount of power required in normal self recovery.


Here's a post I put up many moons ago on another forum about winching coefficents.

This is an excerpt from the very good book 'Off road recovery techniques' by Nick Cole.

Friction is a force that offers resistance to motion between surfaces in contact. The coefficient of Friction is a measure of the amount of friction existing between those surfaces. When a load is to be moved horizontally, it is defined as a pull and at any angle away from horizontal is defined as lifting, when a vector addition of the relative forces has to be used.

Pulling

E=uW

Lifting

E=W(u cos a + sin a)

E is the effort to move the load
W is the weight of the casulty
u is the coefficient of friction
a is the angle from horizontal 


Friction imposes an initial resistance to movement, and once moving it reduces slightly to the figures listed. These values can only be established by experiment and can change by a marked amount, particularly in the presence of lubricants and varying conditions of the two surfaces in contact. It is possible for a coefficient to have a value greater than 1, which is unlikely in practice unless the casualty is below the surface level and pulling builds up material in front as with a bulldozer.

Coefficients of Friction.

Asphalt / rubber       0.5 - 0.8
Rubber / steel      0.6 - 0.9
Rubber / asphalt (wet)  0.25 - 0.75
Rubber / asphalt (dry)   0.5 - 0.8
Rubber / concrete (wet) 0.45 - 0.75
Rubber / concrete (dry) 0.6 - 0.85
Dry masonry / brickwork  0.6 - 0.7
Masonry / dry clay  0.5
Masonry / wet clay  0.3
Timber / stone 0.4
Timber / timber 0.2 - 0.5
Timber / metal  0.2 - 0.6
Wheeled load on tarmac - 0.02 - 0.05
Iron / Stone  0.3 - 0.7
Lubricated metal surfaces 0.1 - 0.2
Vehicle in wet and clinging clay 0.5
Vehicle in hard wet sand 0.17
Vehicle in soft wet sand 0.2
Vehicle in soft dry sand 0.25
Vehicle in shallow mud 0.33
Vehicle in bog 0.5
Vehicle in marsh 0.5
Vehicle on gravel 0.2
Vehicle on grass 0.14

If the weight of the vehicle is 2000Kg's in the case of a LWB Frontera and it's stuck in a bog on a flat surface. The effort required to extract it will be

E = 0.5x2000 which is 1000kg's or a 2000lb winch.

For pulling up a slope, the following table is useful

u  / slope angle at which pulling effort is a maximum (degrees)
0.02  /  88.9
0.05 /   87.1
0.1   /   84.3
0.2  /  78.7
0.3  /  73.3
0.4  /  68.2
0.5  /  63.4
0.6   /   59.0
0.7  /  55.0
0.8  /  51.3
0.9  /  48.0
1.0  /  45
1.1  /  42.3
1.2  /  39.8

From the table above, if a LWB Frontera is stuck in a bog (u=0.5) then the largest value of E will be if the vehicle needs towing up a slope of 63.4 degrees (any more and a lifting effect takes place and aids the winch - at 90 degrees the vehicle is just being lifted directly up, so E=W after the initial suction is overcome)

so

E = W (u cos a + sin a)

E = 2000 x((0.5 x cos 63.4) + (sin 63.4)
E = 2000 x (0.2239+0.8942)
E = 2000 x 1.1181

E = 2236.2Kg's.

or 5000lb's <>

(if anyone is any good at maths, can you check mine - it's been a decade or so since I've done trig ;) )

Just picture trying to tow a vehicle up a 63 degree slope in your head though ;)  That is the power winch needed for towing a 2000Kg vehicle through a bog.

[Saffy]

Here's a post I put up many moons ago on another forum about winching coefficents.

REME recovery manual gives much same thing but in a simpler way. It a good way to realise a rolling load requires a fraction of that load to pull regardless if its in its axles in a deep bog. My winch on the 110  is set to 7,500lb by calculation it would only be a concern when trying to do a straight line winch up a 45deg slope in bog, it's the added safety factor that throws things.

I made a basic calculator based on the same calculations simplied some years ago...
http://www.stonefisk.com/winchcalc.htm

[dxmedia]

I made a basic calculator based on the same calculations simplied some years ago...
http://www.stonefisk.com/winchcalc.htm

Tidy